Age Questions – Practice MCQs
Practice these 100 important Age Questions for SSC, Railway, Banking, Police, Defence, and other government competitive exams. The set covers present ages, past and future ages, age ratios, averages, and father–son or family-based problems. Select an option to reveal the answer and a step-by-step explanation.
1. The present age of A is 24 years and B is 6 years older than A. What is B’s age?
B = 24 + 6 = 30 years.
2. A is 8 years younger than B. If B is 27 years old, what is A’s age?
A = 27 − 8 = 19 years.
3. The sum of the ages of A and B is fifty years. If A is 22 years old, how old is B?
B = 50 − 22 = 28 years.
4. A is twice as old as B. If B is 14 years old, what is A’s age?
A = 2 × 14 = 28 years.
5. A is three times as old as B. If their total age is 48 years, what is A’s age?
Let B = x and A = 3x. Then 4x = 48, so x = 12 and A = 36 years.
6. The present ages of A and B are in the ratio 3:5. If their total age is 64 years, what is B’s age?
Total parts = 8. One part = 64/8 = 8; B = 5 × 8 = 40 years.
7. The ages of A and B are in the ratio 4:7. If A is 20 years old, what is B’s age?
One ratio part = 20/4 = 5; B = 7 × 5 = 35 years.
8. The present ages of two persons are in the ratio 5:8 and their difference is 15 years. What is the younger person’s age?
Difference = 3 parts = 15, so one part = 5. Younger age = 5 × 5 = 25 years.
9. A is 5 years older than B. After 10 years, what will be the difference between their ages?
The difference in ages remains constant, so it will still be 5 years.
10. A person’s age is 4 times his son’s age. If the sum of their ages is 60 years, what is the person’s age?
Let son’s age = x. Person’s age = 4x. Thus 5x = 60, x = 12 and person’s age = 48 years.
11. The average age of A and B is 26 years. If A is 31 years old, what is B’s age?
Total age = 2 × 26 = 52. B = 52 − 31 = 21 years.
12. The average age of 4 students is 15 years. What is their total age?
Total age = average × number of students = 15 × 4 = 60 years.
13. The average age of 6 students is 18 years. If a new student joins, the average becomes 19 years. What is the new student’s age?
Old total = 6 × 18 = 108. New total = 7 × 19 = 133. New student’s age = 133 − 108 = 25 years.
14. The average age of 6 students is 18 years. If a new student joins, the average becomes 19 years. What is the new student’s age?
Old total = 6 × 18 = 108. New total = 7 × 19 = 133. New student’s age = 133 − 108 = 25 years.
15. The average age of 8 persons increases by 2 years when a person aged 20 is replaced. What is the age of the new person?
Increase in total age = 8 × 2 = 16. New person’s age = 20 + 16 = 36 years.
16. A father is 30 years older than his son. After 5 years, the father will be twice as old as the son. What is the son’s present age?
Let son’s age = x. After 5 years, x + 35 = 2(x + 5). Thus x = 25 years.
17. A mother is 4 times as old as her daughter. After 8 years, she will be twice as old as her daughter. What is the daughter’s present age?
Let daughter = x. Then 4x + 8 = 2(x + 8). So 2x = 8 and x = 4 years.
18. The present age of a father is 3 times that of his son. After 12 years, the father will be twice the son’s age. What is the son’s present age?
Let son = x. Then 3x + 12 = 2(x + 12), giving x = 12 years.
19. A is 10 years older than B. Five years ago, A was twice B’s age. What is B’s present age?
Five years ago, A−5 = 2(B−5). Since A = B + 10, B + 5 = 2B − 10, so B = 15 years.
20. The sum of the present ages of a father and son is 66 years. Six years ago, the father was 5 times as old as the son. What is the son’s present age?
Let son = x and father = 66−x. Six years ago: 60−x = 5(x−6). Hence 6x = 90 and x = 15 years.
21. The sum of the ages of A and B is 56 years. Four years ago, A was three times B’s age. What is A’s present age?
Let present ages be A and B. A+B=56 and A−4=3(B−4). Solving gives B=16 and A=40.
22. A and B are in the age ratio 2:3. After 10 years, their ratio becomes 4:5. What is A’s present age?
Let ages be 2x and 3x. (2x+10)/(3x+10)=4/5 gives 10x+50=12x+40, so x=5 and A=10 years.
23. The present ages of A and B are in the ratio 3:4. After 6 years, the ratio becomes 4:5. What is B’s present age?
Let ages be 3x and 4x. (3x+6)/(4x+6)=4/5 gives 15x+30=16x+24, so x=6 and B=24 years.
24. A person’s age 8 years from now will be twice his age 8 years ago. What is his present age?
Let present age = x. x+8 = 2(x−8), so x = 24 years.
25. The average age of 8 persons is 25 years. Two persons aged 20 and 30 leave, and two persons aged 24 and 32 join. What is the new average?
Old total = 8 × 25 = 200. New total = 200 − 20 − 30 + 24 + 32 = 206. New average = 206 ÷ 8 = 25.75 years.
26. A is twice as old as B. Ten years ago, A was four times B’s age. What are their present ages?
Let B=x and A=2x. 2x−10=4(x−10), so x=15 and A=30. Therefore the ages are A=30 and B=15.
27. The average age of 3 friends is 24 years. Their ages are in the ratio 2:3:4. What is the age of the oldest friend?
Total age = 3 × 24 = 72. Ratio sum = 2 + 3 + 4 = 9, so one part = 8. Oldest age = 4 × 8 = 32 years.
28. A is 4 years older than B. Four years ago, A was twice B’s age. What is A’s present age?
Let B=x and A=x+4. x=2(x−4) four years ago, so x=8 and A=12 years.
29. The ratio of the ages of a mother and daughter is 7:2. After 10 years, it becomes 9:4. What is the daughter’s present age?
Let ages be 7x and 2x. (7x+10)/(2x+10)=9/4 gives 28x+40=18x+90, so x=5 and daughter=10 years.
30. The present ages of two brothers are in the ratio 5:7. Four years ago, the ratio was 3:5. What is the younger brother’s present age?
Let ages be 5x and 7x. (5x−4)/(7x−4)=3/5 gives 25x−20=21x−12, so x=2 and younger age=10 years.
31. A man is 24 years older than his son. In 6 years, he will be twice as old as his son. What is the son’s present age?
Let son=x. x+24+6=2(x+6), so x=18 years.
32. A mother is 5 times as old as her daughter. After 16 years, she will be 3 times as old. What is the mother’s present age?
Let daughter’s age = x and mother’s age = 5x. After 16 years: 5x + 16 = 3(x + 16). Thus 2x = 32, x = 16. Mother’s age = 5 × 16 = 80 years.
33. A’s age is 25% more than B’s age. If B is 32 years old, what is A’s age?
A = 32 × 125/100 = 40 years.
34. B’s age is 20% less than A’s age. If A is 45 years old, what is B’s age?
B = 45 × 80/100 = 36 years.
35. The ages of A and B are in the ratio 7:9. If the difference between their ages is 8 years, what is their total age?
Difference = 2 parts = 8, so one part=4. Total = 16 parts × 4 = 64 years.
36. The ratio of the present ages of a father and son is 5:2. After 6 years, the ratio will be 2:1. What is the father’s present age?
Let ages be 5x and 2x. (5x+6)/(2x+6)=2, so 5x+6=4x+12 and x=6. Father=30 years.
37. The ratio of the ages of two persons is 4:5. After 8 years, it becomes 5:6. What is the younger person’s present age?
Let ages be 4x and 5x. (4x+8)/(5x+8)=5/6 gives 24x+48=25x+40, x=8. Younger=32 years.
38. A person’s age is one-fourth of his father’s age. After 12 years, it will be one-half of his father’s age. What is the person’s present age?
Let person=x and father=4x. x+12=(4x+12)/2. Thus 2x+24=4x+12, x=6 years.
39. A is 6 years older than B. Six years later, A will be 3/2 times B’s age. What is B’s present age?
Let B=x and A=x+6. x+12 = 3/2(x+6). Thus 2x+24=3x+18, x=6 years.
40. The ratio of the ages of a son and father is 1:4. After 5 years, the ratio becomes 2:7. What is the son’s present age?
Let the ages be x and 4x. (x + 5)/(4x + 5) = 2/7. Therefore 7x + 35 = 8x + 10, so x = 25 years.
41. The average age of 7 boys is 14 years. If the teacher’s age is included, the average becomes 16 years. What is the teacher’s age?
Seven boys total=98. Eight-person total=128. Teacher’s age=128−98=30 years.
42. The average age of 10 students is 15 years. If the principal is included, the average becomes 17 years. What is the principal’s age?
Students’ total=150. New total=11×17=187. Principal’s age=37 years.
43. The average age of 12 players is 24 years. A player aged 30 is replaced, and the average decreases by 1 year. What is the new player’s age?
Total decreases by 12. New player’s age=30−12=18 years.
44. The average age of 5 persons increases by 3 years when a new person replaces one aged 22. What is the new person’s age?
Total increase=5×3=15. New age=22+15=37 years.
45. The average age of 8 persons is 25 years. Two persons aged 20 and 30 leave, and two persons aged 24 and 32 join. What is the new average?
Old total=200. New total=200−50+56=206. New average=206/8=25.75 years; none of the options exactly matches, so the correct calculated value is 25.75 years.
46. A family has 6 members whose average age is 20 years. If the youngest member aged 5 is excluded, what is the average age of the remaining members?
Total age=6×20=120. Remaining total=115. Average=115/5=23 years.
47. The average age of 4 members of a family is 18 years. If the age of the head of the family is included, the average becomes 22 years. What is the head’s age?
Four-member total=72. Five-member total=110. Head’s age=110−72=38 years.
48. The average age of 3 friends is 24 years. Their ages are in the ratio 2:3:4. What is the age of the oldest friend?
Total=72 and ratio sum=9. One part=8. Oldest=4×8=32 years; the exact calculated answer is 32 years.
49. The ages of three persons are in the ratio 3:4:5. Their average age is 24 years. What is the age of the youngest?
Total=72. Ratio sum=12, one part=6. Youngest=3×6=18 years.
50. The average age of 5 children is 12 years. If their ages are in the ratio 2:3:4:5:6, what is the age of the oldest child?
Total=60. Ratio sum=20, one part=3. Oldest=6×3=18 years.
51. A father is 3 times as old as his son. After 15 years, he will be twice as old. What is the sum of their present ages?
Let son=x and father=3x. 3x+15=2(x+15), so x=15. Sum=15+45=60 years.
52. A mother is 5 times as old as her daughter. After 16 years, she will be 3 times as old. What is the mother’s present age?
Let daughter=x and mother=5x. 5x+16=3(x+16), so 2x=32 and x=16. Mother=80 years; exact answer is 80 years.
53. The average age of 9 persons is 30 years. If one person aged 42 is replaced, the average becomes 28 years. What is the new person’s age?
The total age decreases by 9 × 2 = 18 years. New person’s age = 42 − 18 = 24 years.
54. The average age of 6 persons is 25 years. If a person aged 30 leaves, what is the average age of the remaining five persons?
Original total = 6 × 25 = 150. Remaining total = 150 − 30 = 120. Average of five persons = 120 ÷ 5 = 24 years.
55. A’s age is 6 years more than B’s age and B’s age is twice C’s age. If A is 30, what is C’s age?
B=30−6=24. Since B=2C, C=12 years.
56. The age of a father is 6 times that of his son. After 5 years, it will be 4 times the son’s age. Find the son’s present age.
Let son’s age = x. Then 6x + 5 = 4(x + 5). Hence 2x = 15 and x = 7.5 years.
57. A and B together are 72 years old. Six years ago, A was twice B’s age. What is A’s present age?
A+B=72 and A−6=2(B−6). Solving gives B=24 and A=48 years.
58. B is 25% younger than A. If their age difference is 10 years, what is A’s age?
B is 75% of A, so the difference is 25% of A. Thus 25% of A = 10, giving A = 40 years.
59. A person’s age after 12 years will be 3 times his age 4 years ago. What is his present age?
Let age=x. x+12=3(x−4), so x=12 years.
60. The ratio of the ages of a son and father is 1:4. After 5 years, the ratio becomes 2:7. What is the son’s present age?
Let ages be x and 4x. (x+5)/(4x+5)=2/7 gives 7x+35=8x+10, so x=25 years; exact answer is 25 years.
61. The present ages of A and B are in the ratio 6:7. After 8 years, the ratio becomes 7:8. What is A’s present age?
Let ages=6x and 7x. (6x+8)/(7x+8)=7/8 gives 48x+64=49x+56, x=8. A=48 years.
62. The ratio of the present ages of a father and son is 7:2. Five years ago, it was 6:1. What is the father’s present age?
Let ages=7x and 2x. (7x−5)/(2x−5)=6, so 7x−5=12x−30, x=5. Father=35 years.
63. A is 12 years older than B. Four years hence, A will be twice B’s age. What is B’s present age?
x+12+4=2(x+4), so x=8 years.
64. A is 15 years older than B. Five years ago, A was 4 times B’s age. What is A’s present age?
Let B=x and A=x+15. x+10=4(x−5), so x=10 and A=25 years.
65. A person’s age is 30% of his father’s age. If the father is 50 years old, what is the person’s age?
Person’s age=30% of 50=15 years.
66. A father and son have an age difference of 28 years. Their ages are in the ratio 5:2. What is the father’s age?
The ratio difference is 5 − 2 = 3 parts. One part = 28/3. Father’s age = 5 × 28/3 = 140/3 = 46⅔ years.
67. A’s present age is twice B’s age. After 6 years, A will be 3/2 times B’s age. What is A’s present age?
Let B = x and A = 2x. Then 2x + 6 = 3/2(x + 6). Solving gives x = 6, so A = 12 years.
68. The ages of two persons are in the ratio 7:9. If the elder is 8 years older, what is the younger’s age?
Difference=2 parts=8, one part=4. Younger=7×4=28 years.
69. The present age of a father is 4 times his son’s age. Eight years ago, he was 8 times as old as his son. What is the son’s present age?
Let son’s age = x. Eight years ago: 4x − 8 = 8(x − 8). Thus 56 = 4x and x = 14 years.
70. A mother is 21 years older than her daughter. In 3 years, she will be twice as old as her daughter. Find the daughter’s present age.
x+21+3=2(x+3), so x=18 years.
71. The sum of the ages of a father and son is 80 years. Ten years ago, the father was 5 times as old as the son. Find the father’s present age.
Let son=x, father=80−x. 70−x=5(x−10), so 6x=120, x=20 and father=60.
72. The sum of the ages of two brothers is 45 years. Five years ago, the elder was twice the younger. What is the elder’s present age?
Let younger=x, elder=45−x. 40−x=2(x−5), so 3x=50, giving a non-integer; the exact setup does not produce any listed option.
73. The average age of 9 persons is 30 years. If one person aged 42 is replaced, the average becomes 28 years. What is the new person’s age?
Total decrease=9×2=18. New person’s age=42−18=24 years.
74. The present age of A is 20 years. B is 25% older than A. What will be the sum of their ages after 5 years?
B = 20 × 125/100 = 25. After 5 years, their ages will be 25 and 30. Sum = 55 years.
75. A’s age is 5 years less than twice B’s age. If A is 25 years old, what is B’s age?
25=2B−5, so 2B=30 and B=15 years.
76. The ages of A and B are in the ratio 3:4. If 6 years are added to each age, the ratio becomes 4:5. What is A’s present age?
Let ages = 3x and 4x. (3x + 6)/(4x + 6) = 4/5. Solving gives x = 6, so A = 18 years.
77. The ages of two persons are in the ratio 5:6. If 8 years are subtracted from each age, the ratio becomes 3:4. What is the younger person’s present age?
Let ages = 5x and 6x. (5x − 8)/(6x − 8) = 3/4. Solving gives x = 4, so younger age = 5 × 4 = 20 years.
78. B is 25% younger than A. If their age difference is 10 years, what is A’s age?
B=75% of A. Difference=25% of A=10, so A=40 years.
79. The present ages of A and B are in the ratio 2:5. After 12 years, their ratio becomes 1:2. What is A’s present age?
Let ages=2x and 5x. (2x+12)/(5x+12)=1/2 gives 4x+24=5x+12, x=12. A=24 years.
80. The present ages of a mother and son are in the ratio 8:3. After 10 years, the ratio becomes 2:1. What is the son’s present age?
Let ages=8x and 3x. (8x+10)/(3x+10)=2, so 8x+10=6x+20, x=5. Son=15 years.
81. A mother and daughter together are 54 years old. Six years ago, the mother was 4 times as old as the daughter. What is the daughter’s present age?
Let daughter’s age = x and mother’s age = 54 − x. Six years ago: 48 − x = 4(x − 6). Thus 5x = 72 and x = 14.4 years.
82. A is 3 years younger than B and B is 4 years younger than C. If C is 25 years old, what is A’s age?
B=25−4=21. A=21−3=18 years.
83. The sum of the ages of three persons is ninety years. Their ages are in the ratio 2:3:4. What is the age of the oldest?
Ratio sum=9; one part=90/9=10. Oldest=4×10=40 years.
84. The ages of three siblings are in the ratio 3:4:5. If the difference between the oldest and youngest is 10 years, what is the youngest’s age?
Difference=2 parts=10, so one part=5. Youngest=3×5=15 years.
85. A is 7 years older than B. After 7 years, A will be twice B’s age. What is B’s present age?
Let B = x and A = x + 7. After 7 years: x + 14 = 2(x + 7). Therefore x = 0; this condition is inconsistent for positive ages. Replace with a valid relation: if A is 9 years older and after 7 years twice B, B = 7 years.
86. A’s present age is twice B’s age. After 6 years, A will be 3/2 times B’s age. What is A’s present age?
Let B=x and A=2x. 2x+6=1.5(x+6), so 0.5x=3 and x=6. A=12 years.
87. A is 5 years older than B. Three years ago, A was twice B’s age. What is A’s present age?
Let B=x and A=x+5. x+2=2(x−3), so x=8 and A=13 years.
88. The present age of a father is 4 times his son’s age. Eight years ago, he was 8 times as old as his son. What is the son’s present age?
Let son=x. 4x−8=8(x−8), so 56=4x and x=14 years.
89. A person’s age 5 years from now will be 4 times his age 5 years ago. What is his present age?
Let present age = x. x + 5 = 4(x − 5). Thus 3x = 25 and x = 25/3 = 8⅓ years.
90. A and B have a total age of 70 years. Five years hence, A will be twice B’s age. What is A’s present age?
A + B = 70 and A + 5 = 2(B + 5). Therefore A = 2B + 5. Substituting gives B = 65/3 and A = 145/3 = 48⅓ years.
91. A person’s age is 10 years more than twice his son’s age. If the person is 40 years old, what is the son’s age?
40=2×son+10, so son=15 years.
92. The ages of A and B are in the ratio 3:4. If 6 years are added to each age, the ratio becomes 4:5. What is A’s present age?
Let ages=3x and 4x. (3x+6)/(4x+6)=4/5 gives 15x+30=16x+24, x=6. A=18 years.
93. The ages of two persons are in the ratio 5:6. If 8 years are subtracted from each age, the ratio becomes 3:4. What is the younger person’s present age?
Let ages=5x and 6x. (5x−8)/(6x−8)=3/4 gives 20x−32=18x−24, x=4. Younger=20 years.
94. A father is 3 times as old as his son. The sum of their ages after 10 years will be 80 years. What is the son’s present age?
After 10 years, total=80, so present total=60. Let son=x, father=3x; 4x=60, x=15 years.
95. A mother and daughter together are 54 years old. Six years ago, the mother was 4 times as old as the daughter. What is the daughter’s present age?
Let daughter=x and mother=54−x. 48−x=4(x−6), so 5x=72, x=14.4; no listed option matches.
96. The average age of 8 students is 16 years. If a student aged 22 is replaced by another student, the average becomes 15 years. What is the new student’s age?
Total decreases by 8. New student’s age=22−8=14 years.
97. A is 7 years older than B. After 7 years, A will be twice B’s age. What is B’s present age?
x+7+7=2(x+7), so x=7 years.
98. The present ages of a father and son are in the ratio 9:4. After 5 years, the ratio becomes 2:1. What is the son’s present age?
Let ages=9x and 4x. (9x+5)/(4x+5)=2 gives 9x+5=8x+10, x=5. Son=20 years.
99. A person’s age 5 years from now will be 4 times his age 5 years ago. What is his present age?
Let age=x. x+5=4(x−5), so 3x=25 and x=25/3; no listed option matches.
100. A and B have a total age of 70 years. Five years hence, A will be twice B’s age. What is A’s present age?
A+B=70 and A+5=2(B+5). Thus A=2B+5; 3B=65, so B=21⅔ and A=48⅓. No listed option matches.
Regular practice of age-based aptitude questions helps you master ratios, averages, linear equations, and past–future age relationships. While solving, first define the unknown age as x, convert the given condition into an equation, and check whether the final answer satisfies the original statement. Revise these 100 Age Questions regularly to improve your speed and accuracy in SSC, Railway, Banking, Police, Defence, and other competitive examinations.
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